inaccurate. personally experienced otherwise.RunningWithScissors » 28 Aug 2022, 10:12 am » wrote: ↑ In all my years of living, there are two very important things I want all youngsters to know...
One, don't get married on Valentine's Day. You will get divorced, and then that day will be **** up for the rest of your life in every subsequent relationship...
That's incorrect. Outcome #1 says that if it's Even then you have 3 marbles left, you don't know if it's heavier or lighter, and only have one more chance to weigh them. So you have to rely on luck that it is Odd to get to your solution. Remember, this has to work every time, in the same manner. No changes, and no luck involved.Cannonpointer » 28 Aug 2022, 9:53 am » wrote: ↑ So, your PM delivered ONE viable solution to the problem. If you work my solution, you will find that it works in every scenario. It all comes down to the second weighing, and bringing the suspect list down to no more than three. That is what my solution accomplishes in each of the three possible outcomes.
Second weighing:
Sequester 3 from side a. Move two from side b to side a, and place one control with the remaining 2 on side b. Weigh 3 against 3.
Outcomes:
1. Even: The 3 sequestered are the suspects
2. Odd: side a is now HEAVIER, rather than lighter. The two on side a which came over from side b are the suspects.
3. Odd: side a is STILL lighter. The original side a marble may be lighter, or one of the two original side b marbles is heavier: 3 SUSPECTS.
There are only three outcomes of my second weighing, same as yours - and in all three you are left with three suspect marbles, same as yours. The cuprit can be eliminated through a 1x1 and the lighter vs. heavier question is resolved in every case, same as yours.
So there are at least two solutions that work in 100% of scenarios.
If they are even, and the three sequestered came from the lighter side, then lighter is already established, before you go 1x1. If the three sequestered came from the heavier side, then heavier is already established, before you go 1x1.RunningWithScissors » 28 Aug 2022, 10:46 am » wrote: ↑ That's incorrect. Outcome #1 says that if it's Even then you have 3 marbles left, you don't know if it's heavier or lighter, and only have one more chance to weigh them.
I see how your logic works if the scales are tilted on the 1st weighing.
Okay, so we agree that if the scales are ODD, my solution works?RunningWithScissors » 28 Aug 2022, 10:59 am » wrote: ↑ I see how your logic works if the scales are tilted on the 1st weighing.
What if the 1st weighing is even? Now you have 2 more chances, and only moving 2 marbles from side b to side a will not resolve it every time. You need to move 3 marbles.
If they are odd, you still have 3 suspects, with only one chance left. Because if it's odd, you still haven't determined if it's heavier or lighter, since you put yellow marbles on both sides.Cannonpointer » 28 Aug 2022, 11:10 am » wrote: ↑ Okay, so we agree that if the scales are ODD, my solution works?
Let us regress, then, to the issue of having only 4 suspects going into weighing #2, instead of 8.
Place 2 suspects on side a and 1 on side b, with 2 controls and 3 controls, respectively.
3 possible outcomes:
1. Even. The sequestered marble is the suspect. Weigh it 1x1 against any of the 11 remaining controls to determine lighter or heavier. Solved.
2. Odd, side a heavier. Weigh the two suspects on side a 1x1 against each other. If they are even, the one on side b is the odd man, and lighter. If odd, the heavier is the culprit. Solved.
3. Odd, side a is lighter. Weigh the two suspects on side 1x1 a against each other. If they are even, the one on side b is the odd man, and heavier. If odd, the lighter is the culprit. Solved.
If it is odd, then side a is either lighter or heavier. THERE ARE ONLY TWO SUSPECT MARBLES ON SIDE A.RunningWithScissors » 28 Aug 2022, 11:13 am » wrote: ↑ If they are odd, you still have 3 suspects, with only one chance left. Because if it's odd, you still haven't determined if it's heavier or lighter, since you put yellow marbles on both sides.
RunningWithScissors » 28 Aug 2022, 11:16 am » wrote: ↑ You would know that it is one of the 3, but you can't tell if it's heavier or lighter, to figure it out on the final weighing.
The ultimate solution is just to get a digital scale.... :-)
Assume step 1 is even. that means one of your 4 yellow marbles is different.Cannonpointer » 28 Aug 2022, 11:21 am » wrote: ↑ If it is odd, then side a is either lighter or heavier. THERE ARE ONLY TWO SUSPECT MARBLES ON SIDE A.
Weigh them against each other. If side a was lighter, and they are even, then the side b suspect marble is the culprit - and heavier. If they are odd, then the lighter one is the culprit.
If side a was heavier, the elimination works the same.
Yes. 4 suspects, 8 controls.RunningWithScissors » 28 Aug 2022, 11:29 am » wrote: ↑ Assume step 1 is even. that means one of your 4 yellow marbles is different.
Correct. We do not yet know lighter or heavier. We get that information in the 1x1, thus:RunningWithScissors » 28 Aug 2022, 11:29 am » wrote: ↑If you put yellow marbles on both sides, 2 on the left, 1 on the right, and move the blue marbles accordingly so that there's 4 per side... If you get an unbalanced result, you know it's one of the 3 yellow marbles. But you don't know if it's heavier or lighter yet. You just know one of the three is the culprit. And now you only have one chance left.
Yes, but 2 are on the light side and one is on the heavy side (or the reverse, as the case may be). So the side the culprit is on answers to heavier or lighter.RunningWithScissors » 28 Aug 2022, 11:42 am » wrote: ↑ At that point you have 3 yellow marbles, one of which is different, and you don't know if it's heavier or lighter. How do you resolve that with just one more weighing?
If the two came from the lighter side, the lighter is the culprit. If the two were on the heavier side, the heavier is the culprit.RunningWithScissors » 28 Aug 2022, 11:42 am » wrote: ↑ If you weigh 1x1, and they're different, how do you know if it's heavier or lighter?
Whichever side of the scale it was on - heavier or lighter - determines that.RunningWithScissors » 28 Aug 2022, 11:42 am » wrote: ↑ If you weigh 1x1, and they're the same, how do you know if the 3rd one is heavier or lighter?