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Monderegal
5 Apr 2023 7:17 pm
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Child Groomer, Sexual Predator
1,231 posts
John » 05 Apr 2023, 6:35 pm » wrote: ↑ A constant force, acting on a particle of mass m, will produce a constant acceleration a. Let us choose the x-axis to be in the common direction of F and a. What is the work done by this force on the particle in causing a displacement x? We have, for constant acceleration, the relations a = ( V - v ) / t and x = ½ ( V + v ) t. Here v is the particle's speed at t = 0 and V is its speed at time t. The the work done is W = F x = m a x = m ( ( V - v ) / t ) ( ½ ( V + v ) ) t = ½ m V² - ½ m v². We call one-half the product of the mass of a body and the square of its speed the kinetic energy of the body. If we represent kinetic energy by the symbol K, then K = ½ m v². We may then state the above equation in this way: The work done by the resultant force acting on a particle is equal to the change in the kinetic energy of the particle.
An object at rest tends to stay at rest. An object in motion tends to stay in motion. That's the basic concept. Newton's first law of motion. You have some of the three laws of motion down but it's a little jumbled with the equations. In other words its measured by potential energy versus kinetic energy. By the way, in there somewhere you have K as the measurement for kinetic energy. K is typically the value for a temperature measure called Kelvin.
 
 
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