27 Aug 2022 1:54 am
Well it's one of the possibilities. Regardless, the solution will be the same. It is the process that defines the solution. The steps to the solution will be the same regardless, and never fail.DeezerShoove » 26 Aug 2022, 7:46 pm » wrote: ↑ I am with you for the first step.
4x4 gets you a control group (or two if they balance).
The remaining odd four are easy to sort in two weighings.
If the first 4x4 do not balance, isn't this where the "solution" and actually the problem really is?
How do you find 1 odd ball out of 8 in just two weighings?
Regardless of the first 4x4 weighing, you have 4 in a control group. You have to use that. But not all of them, just 3 and move the others around.
That's why I say you can't get lucky, because if you do, I will falsify that. But you're so close!